Find the zeros of quadeatic polynomial x²+7x+10.
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Answer:
Let
p(x)=x2 +7x+10
comparing with p(x)=ax 2 +bx+ca=1,b=7,c=10
p(x)=x 2 +7x+10
⇒x 2 +5x+2x+10
⇒x(x+5)+2(x+5)
⇒(x+2)(x+5)
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