Question

find the zeros of quadratic 16xsq-3

Answer 1

Heya ✋

Let see your answer !!!!

$let \: p(x) = 16x ^{2} - 3 \\ p(x) = 0 \\ = > 16x ^{2} - 3 = 0 \\ = > 16x ^{2} = 3 \\ = > x ^{2} = 3 \div 16 \\ = > x = \sqrt{3 \div 16} \\ = > x = \sqrt{3 \div 4}$


Hence , √3/4 is the zero of the polynomial p(x).







Thanks :))))

Answer 2

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