Question

Find the zeros of quadratic equation x2

- 6x +8 =0 and check the relation between the zero and its coefficients.​

Answer 1

Answer:

zeroes are 2 or 4

Step-by-step explanation:

x²-6x+8=0

A=1, b= -6, c=8

x²-x(4+2)+8=0

x²-4x-2x+8=0

taking x common from (x²-4x) and taking -2 common from(-2x+8)

x(x-4)-2(x-4)=0

x-2=0 and x-4=0

x=2 andx=4

let α=2 β=4

sum of zeroes=α+β=-b/a

2+4=-(-6)/1

6=6

product of zeroes

α×β=c/a

2×4=8/1

8=8

hence verified