Question

find the zeros of quadratic polynomial 4x^2+8x​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

The given polynomial is as follows :-

4 {x}^{2} - 8x4x

2

−8x

\rule{200}{2}

To find :- zeroes of the polynomial.

\rule{200}{2}

We can say that :-

\begin{gathered}4 {x}^{2} - 8x \\ \\ \\ = 4x(x - 2)\end{gathered}

4x

2

−8x

=4x(x−2)

\rule{200}{2}

To get the zeroes, we need to equate the polynomial with zero.

Hence, equating the polynomial with its zeroes :-

\rule{200}{2}

4x(x - 2) = 04x(x−2)=0

Now, here,

Either 4x will be zero or (x-2) will be zero.

Therefore :-

\begin{gathered}4x = 0 \\ \\ x = 0\end{gathered}

4x=0

x=0

Or,

\begin{gathered}x - 2 = 0 \\ \\ x = 2\end{gathered}

x−2=0

x=2

\rule{200}{2}

Thus,

Zeroes of the polynomial are 0 and 2

\rule{200}{2}

Hence, solved!