Question

Find the zeros of quadratic polynomial 6 x square - 3 - 7x and verify the relationship between the zeros and the coefficients

Answer 1

6x²-7x-3=0

==> 6x²-9x+2x-3=0

==> 3x(2x-3)+1(2x-3)=0

==>(3x+1)(2x-3)=0

So:

either x = -1/3

or x = 3/2

Putting these values we need to verifyL

6x²-7x-3

==> 6/9+7/3-3=0

==>(6+21)/9-3=0

==>27/9-3=0

==>3-3=0

So it is correct

6x²-7x-3=0

==> 6*9/4 - 7*3/2 - 3=0

==> 27/2 - 21/2-3=0

==>6/2-3=0

==>3-3=0

Hence verified.

Hope it helps

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