find the zeros of quadratic polynomial 6x^2 - 3 - 7x and verify the relationship between zeros and coefficient
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Step-by-step explanation:
6x^2 - 7x - 3
6x^2 - 9x + 2x - 3
3x ( 2x - 3 ) + 1 ( 2x - 3 )
( 2x - 3 ) ( 3x + 1 )
2x - 3 = 0
x = 3/2
3x + 1 = 0
x = -1/3
sum of zeros = 3/2 + ( -1/3 )
= 3/2 - 1/3
= 9 - 2/6
= 7/6 = [ - coefficient of x / coefficient of x^2 ]
product of zeros = 3/2 * -1/3
= -3/6 = [ constant term / coefficient of x^2 ]
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