Find the zeros of quadratic polynomial 6x²-3-7x
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Step-by-step explanation:
6x^2-7x-3 = 6x^2-9x+2x-3
= 3x(2x-3) + 1(2x-3)
= (3x+1) (2x-3)
x=-1/3 or x=3/2
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