Question

find the zeros of quadratic polynomial 6x²-3-7x​

Answer 1

hey mate...!

here is your answer...

check the attachment...

hope it helps...

please mark me as the brainliest...

Answer 2

Answer:

$\\ \tt \: 6 {x}^{2} - 7x - 3 \\ \\ \\ \tt 6 {x}^{2} - 9x + 2x - 3 \\ \\ \\ \tt \: 3x \: (2x - 3) \: + 1 \: (2x - 3) \\ \\ \\ \tt \: (3x + 1) \: (2x - 3)$

So, zeroes are 1/3 and 3/2.

$\\ \tt \: \: 3x +1 = 0 \\ \\ \implies \tt \: x = - \frac { 1}{3}$

or,

$\\ \tt \: \: 2x - 3 = 0 \\ \\ \implies \tt \: x = \frac{3}{2}$