find the zeros of quadratic polynomial 6x²-x-1
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Answered by
11
6x^2-x-1=6x^2-3x+2x-1 -6= -3×2
=3x(2x-1)+1(2x-1) -1=-3+2
=(3x+1)(2x-1)
3x+1=0. 2x-1=0
3x=-1. 2x=1
x=-1/3. x=1/2
=3x(2x-1)+1(2x-1) -1=-3+2
=(3x+1)(2x-1)
3x+1=0. 2x-1=0
3x=-1. 2x=1
x=-1/3. x=1/2
Answered by
8
Hello
The zeros of this quadratic Polynomials can be founded b using the method of splitting the middle term
Given,
6x² - x - 1 = 0
6x² - 3x + 2x - 1 = 0
3x(2x - 1) + (2x - 1) = 0
(2x - 1)(3x + 1) = 0
2x - 1 = 0
x = 1/2
3x + 1 = 0
x = -1/3
Thus,
1/2 and -1/3 are it's zeros
The zeros of this quadratic Polynomials can be founded b using the method of splitting the middle term
Given,
6x² - x - 1 = 0
6x² - 3x + 2x - 1 = 0
3x(2x - 1) + (2x - 1) = 0
(2x - 1)(3x + 1) = 0
2x - 1 = 0
x = 1/2
3x + 1 = 0
x = -1/3
Thus,
1/2 and -1/3 are it's zeros
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