Question

find the zeros of quadratic polynomial 9t2 - 6t +1 and find the relationship between zeros and its coefficient

Answer 1

I hope this will help you....

Answer 2

9t²-6t+1
=9t²-3t-3t+1
=3t(3t-1)-1(3t-1)
=(3t-1)(3t-1)
Either,
3t-1=0
or, t=1/3
And,
3t-1=0
or, t=1/3
Relationship between zeroes and coefficient,

Sum of zeroes=-(coefficient of t) /coefficient of t²
or, 1/3+1/3 = -(-6)/9
or,2/3 = 2/3
Hence, RHS = LHS

Product of zeroes=constant term/coefficient of t²
or, 1/3 x 1/3 = 1/9
or, 1/9 = 1/9
Hence, RHS = LHS

HENCE, SOLVED....