Question

Find the zeros of quadratic polynomial and verify the relationship between zeros and coefficients. (4x ^ 2 - 4x - 3)​

Answer 1

Answer:

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Answer 2

Answer:

Let f(x) = 4x2 ˗ 4x ˗ 3

= 4x2 ˗ (6x ˗ 2x) ˗ 3

= 4x^2 ˗ 6x + 2x ˗ 3

= 2x (2x ˗ 3) + 1(2x ˗ 3)

= (2x + 1) (2x ˗ 3)

To find the zeroes, set f(x) = 0

(2x + 1) (2x ˗ 3)= 0

2x + 1 = 0 or 2x ˗ 3 = 0

x = -1/2 or x = 3/2

Again,

Sum of zeroes = (-1/2) + (3/2) = (-1+3)/2 = 2/2 = -b/a =

(-Coefficient of x)/(Cofficient of x2)

Product of zeroes = (-1/2)(3/2) = (-3)/4 = c/a

= Constant term / Coefficient of x2