Question

find the zeros of quadratic polynomial p(x) =4x^2-4x​

Answer 1

Step-by-step explanation:

find the zeros of quadratic polynomial p(x) =4x^2-4x​

P(x)=4x  

2

+24x+36

Here, a=4,b=24,c=36

p(x)=4x  

2

+12x+12x+36

=4x(x+3)+12(x+3)

=(x+3)(4x+12)

=4(x+3)  

2

 

So, the zeros of quadratic polynomial is −3 and −3.  

Let α=−3 and β=−3

Sum of zeros = α+β=−3−3=−6

Sum of zeros =−  

coefficient ofx  

2

 

coefficient ofx

​

 

−  

a

b

​

=  

4

−24

​

=−6

So, sum of zeros =α+β=−  

coefficient ofx  

2

 

coefficient ofx

​

 

Product of zeros =αβ=(−3)(−3)=9

Also, product of zeros =  

coefficient ofx  

2

 

constant term

​

 

=  

a

c

​

=  

4

36

​

=9

So, product of zeros =αβ=  

cofficient ofx  

2

 

constant term

​

Answer 2

Answer:

So Answer is (1,1)

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