find the zeros of quadratic polynomial P(x)=x²-x-72 and find the relationship between zeros and its coefficient
Answers
Answered by
93
AnswEr:-
Given:-
- P(x)=x²-x-72
To find:-
- Zeroes of the polynomial & the relationship btw zeroes and co-efficients.
Solution:-
Given , P(x) = x²-x-72
⇒ x²-x-72=0
⇒ x²-9x+8x -72 =0
⇒ x(x-9) +8(x-9) =0
⇒ (x+8)(x-9)=0
⇒ x+8 = 0 (OR) x-9 = 0
⇒ x = -8 , 9
∴ Zeroes of polynomial are -8 ,9.
Relationship btw zeroes and co-efficients:-
If ax²+bx+c = 0 is a polynomial , where a≠0 & αβ are zeroes of the polynomial ,
❥ αβ = c/a
❥ α+β = -b/a
According to question :
➾ αβ = c/a
⇒ (9)(-8) = -72/1
⇒ - 72 = -72
⇒ 1 = 1 .
➾ α + β = -b/a
⇒ 9 + (-8) = -(-1)/1
⇒ 1 = 1 .
Hence verified!
____________________
Answered by
91
Therefore,
So,
- a = 1
- b = -1
- c = -72
we have to verify,
now,
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