find the zeros of quadratic polynomial root 3x^2-8x+4 root 3
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Answered by
35
Hey!!!!
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=> √3x² - 8x + 4√3 = 0
=> √3x² - 6x - 2x + 4√3 = 0
=> √3x(x - 2√3) - 2(x - 2√3) = 0
=> (√3x - 2)(x - 2√3) = 0
Thus x = 2/√3 or x = 2√3
Hope this helps ✌️
I'm back
=> √3x² - 8x + 4√3 = 0
=> √3x² - 6x - 2x + 4√3 = 0
=> √3x(x - 2√3) - 2(x - 2√3) = 0
=> (√3x - 2)(x - 2√3) = 0
Thus x = 2/√3 or x = 2√3
Hope this helps ✌️
Aryankhunteta:
hey in question there is no root in 3x^2
it is
what it is
it is given
see properly
oh sorry i see
Answered by
16
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