Question

find the zeros of quadratic polynomial

$3x {?}^{2} { - 5x} - 1{2}$
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Answer 1

Answer:

First write the given equation correctly

$\qquad\quad {:}\dashrightarrow\sf 3x^2-5x-12=0$

• Now Factorise

$\qquad\quad {:}\dashrightarrow\sf 3x^2+9x-4x-12=0$

$\qquad\quad {:}\dashrightarrow\sf 3x (x+3)-4 (x+3)=0$

$\qquad\quad {:}\dashrightarrow\sf (x+3)(3x-4)=0$

$\qquad\quad {:}\dashrightarrow\sf (x+3)=0\quad or\quad (3x-4)=0$

$\qquad\quad {:}\dashrightarrow\sf x=-3\quad or\quad=x={\dfrac{4}{3}}$

$\therefore{\underline{\boxed{\sf x=-3\:or\;{\dfrac {4}{3}}}}}$

Answer 2

Answer:

$3 \times + 9 \times - 4 \times 12 = 0$

$3 \times ( \times + 3) - 4( \times + 3) = 0$

$( \times + 3) \: (3 \times - 4) = 0$

$(3 \times - 4) = 0$

$\times 4 \: by \: 3$

$4 \: by \: 3$

Step-by-step explanation:

i hope you understand