Question

find the zeros of quadratic polynomial
$x { }^{2} + 7x + 10$
and verify the relationship between zeros and coefficients​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

x^2+7x+10

Step-by-step explanation:

=x2+5x+2x+10

=x(x+5) +2(x+5)

= (x+5) (x+2)

x+5=0 x+2=0

=> x=-5 => x= -2

Zeroes are -5 & -2

Comparing with ax^2+ bx+c, a = 1 ; b = 7 ; c = 10.

:. Sum of zeroes = - ( coefficient of x) /

coefficient of x^2

=> -5-2 = -b/a

=> -5-2 = -7/1

=> -7 = -7

Hence, verified.

Product of zeroes =constant term/coefficient

of x2

=> -5 × (-2) = c/a

=> +10 = 10/1

=> 10 = 10

Hence, verified.