Question

Find the zeros of quadratic polynomial x square - 2 x minus 8 and verify the relationship between the zeros and

Answer 1

◇ Verified!

$x {}^{2} - 2x - 8 = 0 \\ x {}^{2} - 4x + 2x - 8 = 0 \\ {x}(x - 4) + 2(x - 4) = 0 \\ x - 4 = 0 \\ x + 2 =0 \\ x = 4 \: or \: x = - 2 \\ \alpha + \beta = - b \div a \\ 4 + ( - 2 )= - ( - 2)1 \\ 2 = 2 \\ and \: \\ \alpha \beta = c \div a \: \\ 4 \times - 2 = - 8 \div 1 \\ - 8 = - 8$