Question

Find the zeros of quadratic polynomial X square -3 and verify the relationship between the zeros and the coefficient

Answer 1

Answer:

x2 - 3 = 0

x2 = 3

root 3 and - root 3 are the two zeroes

verify

sum of zeroes =

$- \sqrt{3 } + \sqrt{3} = 0$

product of zeroes=

$\sqrt{3} \times - \sqrt{3} = { \sqrt{} - 3}^{2} = - 3$

a =1 b= 0, c = -3

x2 - 3 =0

verified

Answer 2

Step-by-step explanation:

Question 1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.

(i) x² – 2x – 8

1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.

(i) x² – 2x – 8

(i)

Factorize the equation

Compare the equation with ax² + bx + c = 0

We get

a = 1 ,b=-2 c= -8

To factorize the value we have to find two value which

sum is equal to b =-2

and product is a x c = 1 x -8 = -8

2 and -4 are such number which

sum is 2-4 = - 2

product is 2*-4 = - 8

So we can write middle term -2 x = 2 x – 4 x

We get

x²+2x-4x-8=0

x (x + 2)-4(x + 2) = 0

(x+2) (x-4) = 0

First zero

x + 2 = 0

x = -2

Second zero

x-4 = 0

x = 4

sum of zero -2 + 4 = 2

product of zero 2 x -4 = -8

For a equation ax² + bx + c = 0 , if zeroare α and β ,

Plug the values of a , b and c we get

Sum of zeros -b/a = -(-2/1) = 2

Product of zeros c/a =-8/1 = -8

hope you understand the concept.

pls mark brainliest ✌️✌️