Question

Find the zeros of quadratic polynomial x square + 7 x + 10 and verify the relation between zero and coefficient

Answer 1

this is your solution and concept hope you understand the question if your doubt is cleared I'm glad if not u can ask .. ...... thanks

Answer 2

Given,

$the \: quadratic \: polynomial \: = {x}^{2} + 7x + 10$

$p(x) = {x}^{2} + 7x + 10$

${x}^{2} + 7x + 10 = 0$

${x}^{2} + 2x + 5x + 10$

$x(x + 2) + 5(x + 2)$

$(x + 2)(x + 5)$

$x = - 2 \: and \: - 5$

Therefore the zeros of the polynomial are -2 and -5.

Sum of the zeros of polynomial = -coefficient of x/coefficient of x^2

= -2+(-5)= -7 = -7/1

Product of the zeros of polynomial = Constant term/coefficient of x^2 = -2×-5 = 10 = 10/1

Additional information:

What is a quadratic polynomial?

● A polynomial of degree 2 is called quadratic polynomial.

●More generally, any quadratic polynomial in variable X with real coefficients is of the form ax^2+ bx + c where a,b and care real numbers and a is not equal to zero.

●A quadratic polynomial may be a monomial or binomial or a trinomial.

Examples: 7x^2+1,8x^2+6x+5.