Question

find the zeros of quadratic polynomial x square plus 9x plus 18 ​

Answer 1

Hello!

${x}^{2} + 9x + 18 \\ \\ = {x}^{2} + 6x + 3x + 18 \\ \\ = x(x + 6) + 3(x + 6) \\ \\ = (x + 3)(x + 6)$ So:

$\: x = (- 3) \\ \\ x = ( - 6)$

Thanks!

Hope this helps !

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Answer 2

The equation is x²+9x+18

We will solve it by middle term splitting.

x²+9x+18=0

x²+3x+6x+18=0

x(x+3)+6(x+3)=0

(x+6)(x+3)=0

x+6=0

x=-6

AND

x+3=0

x=-3

So the zeroes of qiven polynomial are
-6 and -3

Hope it will help u
Thank u