find the zeros of quadratic polynomial x2+5+6 and verify the relation between the zeros and the coefficient
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x
2
+5x+6=0
x
2
+2x+3x+6=0
x(x+2)+3(x+3)=0
(x+2)(x+3)=0
x=−2,−3
∴α=−2,β=−3
α+β=−
a
b
−2−3=−
1
5
−5=−5
αβ=
a
c
(−2)(−3)=
1
6
ax
2
+bx+c=0
S
If the roots of x
2
−ax+b=0 are two consecutive odd integers, t hen a
2
−4b is
MEDIUM
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