Question

find the zeros of qudaratic equation x² +15x+ 50​

Answer 1

Answer:

Option (iii) is correct. Step-by-step explanation: Given that, polynomial p(x)=x²-15x+50. let,p(x)=0. ⇒x²-15x+50=0. (∵+50 factors are -10 & -5 to get their sum as-15) & (∵Splitting of -15x is -10x & -5x) ⇒x²-10x-5x+50=0. ⇒x(x-10)-5(x-10)=0. ⇒(x-5)(x-10)=0. case-(1): | case-(2): HOPE THIS WOULD BE HELPFUL FOR ...

Answer 2

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x² + 15x + 50

=> x² + 10x + 5x + 50

=> x(x+10) + 5(x+10)

=> (x+10)(x+5)

=> either x = (-10) or (-5)