find the zeros of qudaratic equation x² +15x+ 50
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Answer:
p(x)=x²-15x+50. let,p(x)=0.
⇒x²-15x+50=0. (∵+50 factors are -10 & -5 to get their sum as-15) & (∵Splitting of -15x is -10x & -5x) ⇒x²-10x-5x+50=0.
⇒x(x-10)-5(x-10)=0.
⇒(x-5)(x-10)=0. case-(1): |
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the equation was x²+15x+50
I know
but the way is correct..may be..
then ?
u done x²-15x+50
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my mistake in reading the question
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Step-by-step explanation:
x²+5x+10x+50
x(x+5)+10(x+5)
(x+5)(x+10)
x=5or x=10
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