find the zeros of root 3 X square + 10 X + 7 root 3 and and relation between the zeros and coefficient
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GIVEN :
Equation : √3x² + 10x + 7√3
Finding the zeroes :
√3x² + 10x + 7√3
Split the middle term.
= √3x² + 7x + 3x + 7√3
= x(√3x + 7) + √3(√3x + 7)
= (x + √3) (√3x + 7) = 0
x = -√3 ; √3x = -7 , x = 7/√3
= -√3 and -7/√3
Zeroes are -√3 and -7/√3
Relation between zeroes and coefficients :
√3x² + 10x + 7√3
a = √3 ; b = 10 ; c = 7√3
Sum of zeroes :
α+β = (-√3) + (-7/√3)
= -√10/√3
= -b/a
= -10/√3
Product of zeroes :
αβ = 7√3 × √3
= 7√3/√3
= 7
= c/a
= 7√3/√3
= 7
Hence, Verified !!
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