Question

find the zeros of th polynomial 6x^2–3–7x​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

=6x²-7x-3

=6x²-7x-3=6x²+2x-9x-3

=6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)

=6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)

=6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)⇒2x-3=0 or ⇒3x+1=0

=6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)⇒2x-3=0 or ⇒3x+1=0⇒x=3/2 or ⇒ x= - 1/3

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