Question

find the zeros of the 2x^2-8x+6​

Answer 1

Answer:

2x²-8x+6

= 2x²-2x-6x+6

= 2x(x-1)-6(x-1)

= (x-1)(2x-6)

Zeroes: x-1 = 0

x = 1

2x-6 = 0

x = 6/2

x = 3

Answer 2

this is your ans.

I hope it helps you