Question

Find the zeros of the cubic polynomial x^3+2x^2-21x-18

Answer 1

Answer:

px=-1

Explanation:

Explanation:

x3−2x2−21x−18x+3=x2−5x−6

x=5±√52−4⋅1⋅(−6)2

x=5±√492

x=5±72

x=6orx=1

Answer 2

Answer:

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Explanation:

x3−2x2−21x−18x+3=x2−5x−6

x=5±√52−4⋅1⋅(−6)2

x=5±√492

x=5±72

x=6orx=1

Px=-1