find the zeros of the cubic polynomial x³-5x²-2x+24 when it is given that the product of its two zeros is 12sir /madam pls say fast pls
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Answer:
3, 4 and -2
Step-by-step explanation:
product of roots of a cubic equation
=. - constant term/ coefficient of X3
let the roots be a, b and c
given, ab = 12
now
abc = -24/1
12c = -24
c = -2
now,
a + b + c = -coefficient of x2/coefficient of X3
a + b + (-2) = -(-5)/1
a + b + 2 = 5
a + b = 5+2
a+b = 7......eqn 1
again
a+b = 7 and ab = 12
a(7-a) = 12
7a - a^2 = 12
a^2 - 7a + 12 = 0
this gives
a = 4, b= 3 or
a=3, b=4
both are same set
so the roots are
3, 4 and -2
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