Question

find the zeros of the f(x)=x^3-x²+20​

Answer 1

Answer:

Polynomial is p(x)=x3+13x2+32x+20

one of the zero is x=−2

One factor of p(x) is (x+2)

⇒ Polynomial becomes p(x)=(x+2)(x2+11x+10) factoring the quadratic, by middle term spletting

⇒ p(x)=(x+2)(x2+10x+x+10)

=(x+2)[x(x+10)+1(x+10)]

=(x+2)[(x+10)(x+1)]

⇒ Other factor are x+10 and x+1

Zeros are x=−10 and x=−1

⇒ All the zeroes of polynomial p(x) are −1,−2 and −10

Answer 2

f(x)=x3+x2−20xf(x)=x3+x2-20x

Set x3+x2−20xx3+x2-20x equal to 00.

x3+x2−20x=0x3+x2-20x=0

Solve for xx.

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