Math, asked by yogesh6558, 11 months ago

Find the zeros of the following polynomial 5√5x^2 +30x+8√5

Answers

Answered by Anonymous
59
Hi ,

5√5x² + 30x + 8√5

splitting the middle term

= 5√5x² + 20x + 10x + 8√5

= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4

= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]

= ( √5x + 4 ) ( 5x + 2√5 )

I hope this helps you.



yogesh6558: thx bro
Answered by bhavanaa98
21
5√5x2+30x+8√5
5√5x2+10+20x+8√5
5x(x+√5) 20(x+√5)
(x+√5) (5x+20)
x=-√5 x=-20/5=-4

i hope this answers help u
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