Find the zeros of the following polynomial 5√5x^2 +30x+8√5
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Answered by
59
Hi ,
5√5x² + 30x + 8√5
splitting the middle term
= 5√5x² + 20x + 10x + 8√5
= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4
= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]
= ( √5x + 4 ) ( 5x + 2√5 )
I hope this helps you.
5√5x² + 30x + 8√5
splitting the middle term
= 5√5x² + 20x + 10x + 8√5
= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4
= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]
= ( √5x + 4 ) ( 5x + 2√5 )
I hope this helps you.
yogesh6558:
thx bro
Answered by
21
5√5x2+30x+8√5
5√5x2+10+20x+8√5
5x(x+√5) 20(x+√5)
(x+√5) (5x+20)
x=-√5 x=-20/5=-4
i hope this answers help u
5√5x2+10+20x+8√5
5x(x+√5) 20(x+√5)
(x+√5) (5x+20)
x=-√5 x=-20/5=-4
i hope this answers help u
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