Question

find the zeros of the following polynomial
5x^2 + 4x = 0​

Answer 1

Answer:

0 & -4/5

Step-by-step explanation:

.............

Answer 2

Given :

5x² + 4x = 0

To be found :

Two zeroes of the given polynomial.

a = 5, b = 4, c = 0

$x = \frac{ - b \pm \sqrt{ {(b)}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - (4) \pm \sqrt{ {(4)}^{2} - 4 \times 5 \times 0 } }{2 \times 5} \\ \\ x = \frac{ - 4 \pm \sqrt{16} }{10} \\ \\ x = \frac{ - 4 \pm 4}{10} \\ \\ x = \frac{ - 4 + 4}{10} \: \: and \: \: \frac{ - 4 - 4}{10} \\ \\ x = \frac{0}{10} \: \: and \: \: \frac{ - 8}{10} \\ \\ x = 0 \: \: and \: \: \frac{ - 4}{5}$

So,

$\boxed{x = 0 \: \: and \: \: \frac{ - 4}{5}}$