Question

find the zeros of the following polynomial and verify the relationship between the zeros and coefficient .......4x2+16x​

Answer 1

Answer:

4x

$4x^{2} + 16x + 0 = p{x} \\ 4x(x + 4) = 0 \\ 4x = 0 \: or \: x + 4 = 0 \\ x = 0 \: or \: x = - 4 \\ \alpha = 0 \: \beta = - 4 \\ 4x ^{2} \: + 16x + 0 \\ a = 4 \: b = 16 \: c = 0 \\ \alpha + \beta = - b \div a \\ \\ \alpha + \beta = 0 + - 4 = - 4 \\ - b \div a = - {16} \div 4 \: = - 4 \\ therefore \: \alpha + \beta = \: - b \div a \\ \alpha \beta = c \div a \\ \alpha \beta = 0 \times - 4 = 0 \\ c \div a \: = 0 \div 4 = 0 \\ therefore \: \alpha \beta = c \div a \: \\ hence \: verified$

Step-by-step explanation:

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Answer 2

answer with explanation...

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