Question

find the zeros of the following polynomials 2x2-3x+1​

Answer 1

Answer:

Polynomial- 2x²-3x+1

2x²-3x+1=0

2x²-2x-x+1=0

2x(x-1)-1(x-1)=0

(x-1)(2x-1)=0

Thus, x= 1(ALPHA) OR x=1/2(BETA)

3ALPHA=3

3BETA=3/2

Sum of Zeroes= 9/2

Product of Zeroes= 9/2

Thus, Polynomial= x²-(Sum of Zeroes)x +(Product of Zeroes)

Thus, Polynomial= x²-9/2x

Answer 2

Sum of zeros=9/2

Product of zeros=9/2

Thus polynomial=x^2-9/2x

Hope it helps you.