Question

Find the zeros of the following quadratic equations and verify relationship between the zeroes and coefficients.
3√3x²-19x+10√3

Answer 1

Step-by-step explanation:

it is factorization method I hope it helps you

Answer 2

Given quadratic equations is 3√3x² - 19x + 10√3

Now, solve it by splitting the middle term

We have to find zeros. So,

⇒ 3√3x² - 19x + 10√3 = 0

⇒ 3√3x² - 9x - 10x + 10√3 = 0

⇒ 3√3x(x - √3) - 10(x - √3) = 0

⇒ (3√3x - 10)(x - √3) = 0

On comparing we get,

⇒ x = 10/3√3, √3

Therefore, zeros are 10/3√3 and √3

Verification

In quadratic polynomial 3√3x² - 19x + 10√3

a = 3√3, b = -19 and c = 10√3

Sum of zeros = -b/a

10/3√3 + √3 = -(-19)/3√3

(10 + 9)/3√3 = 19/3√3

19/3√3 = 19/3√3

Product of zeros = c/a

(10/3√3)(√3) = 10√3/3√3

10/3 = 10/3