Question

find the zeros of the following quadratic polynomial 6x2+7x+2​

Answer 1

$6 {x}^{2} + 4x + 3x + 2 = 0 \\ 2x(3x + 2) + 1(3x + 2) = 0 \\( 3x + 2)(2x + 1) = 0 \\ 3x + 2 = 0 \\ 3x = - 2 \\ x = \frac{ - 2}{3} \\ 2x + 1 = 0 \\ 2x = - 1 \\ x = \frac{ - 1}{2}$

Zeroes of polynomial are:- (-1/2) And (-2/3)

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Answer 2

\begin{lgathered}6 {x}^{2} + 4x + 3x + 2 = 0 \\ 2x(3x + 2) + 1(3x + 2) = 0 \\( 3x + 2)(2x + 1) = 0 \\ 3x + 2 = 0 \\ 3x = - 2 \\ x = \frac{ - 2}{3} \\ 2x + 1 = 0 \\ 2x = - 1 \\ x = \frac{ - 1}{2}\end{lgathered}

6x

2

+4x+3x+2=0

2x(3x+2)+1(3x+2)=0

(3x+2)(2x+1)=0

3x+2=0

3x=−2

x=

3

−2

2x+1=0

2x=−1

x=

2

−1

Zeroes of polynomial are:- (-1/2) And (-2/3)

If its helps then plz mark me as brainliest..