Question

find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficient 2x square - 3 + 5x​

Answer 1

Answer:

2x^2+5x-3

=2x^2+2x+3x-3

=2x(x+1)-3(x+1)

=(2x-3) (x+1)

P(x)=0

(2x-3) (x+1)=0

2x-3=0 or x+1=0

x=3/2 x=-1

$\alpha \: \: \: \: \: \: \: \: \: \: \: \: \: \beta$

Step-by-step explanation:

$\alpha + \beta = 3 - 2 \div 2 \\ = 1 \div 2 \\ \\ \alpha . \beta = - 3 \div 2$

Answer 2

Step-by-step explanation:

2x^2 + 5x - 3 = 0

2x^2 + 6x - x - 3 = 0

2x(x + 3) -1(x + 3) = 0

(2x - 1) (x + 3) = 0

x = 1/2, -3

Zeros are 1/2 and -3

Sum of zeros = -5/2

1/2 - 3 = -5/2

-5/2 = -5/2

Product of zeros = -3/2

-3/2 = -3/2