Question

Find the zeros of the following quadratic polynomial and verify the relation between coefficient and zeroes

Answer 1

Answer:

Quadratic equations are not given but I have some....

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Answer 2

Answer:

Your answer is...

Let f(u)=4u²+8u

To calculate the zeros of the given

equation, put f(u)=0.

4u²+8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,

=> -b/a=-8/4

=> -2

The product of the zeros is,

=> c/a =0/4

=> 0

Hence, it is verified that,

sum of zeros= -coefficient of x / coefficient of x²

And,

product of zeros= constant term / coefficient of x²

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