Question

find the zeros of the following quadratic polynomial and verify the relationship between the zeros and Coefficient 4u square + 8 u

Answer 1

solution:

$4 {u}^{2} + 8u = 0 \\ = > u(4u + 8) = 0 \\ = > u = 0 \: or \: u \: = - 2$
so, zeroes are 0 & -2

sum of zeroes= 0+(-2)= -2= -b/a

Products of zeroes= 0*-2= 0 = c/a

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Hope it helps☺

#Amrit⭐

Answer 2

Hey

Here is your answer,

4u^2 + 8u = 0
4u ( u + 2) =0
4u = 0
u = 0
u + 2 =0
u =-2

Sum of zeroes = 0+(-2)
=-2

Sum of zeroes = -b/a
=-8/4
=-2

Product of zeroes = 0 x -2
=0

Product of zeroes = c/a
=0/4
=0

Hope it helps you!