Question

Find the zeros of the following quadratic polynomial and verify the relationship between the zeroes and the coefficients :
4u² + 8U

THNAK'S IN ADVANCE...... :D

Answer 1

let 4u^2+8u=0
Now taking 4u common
4u (u+2)=0
4u=0, u+2=0
u= 0/4 , u= -2
u= 0, u= -2
Therefore, zeroes of the quadratic polynomial=0,-2
Verification:
Sum of zeroes= -b/a= -8/4= -2
product of zeroes= c/a= 0/4= 0
verified.

Answer 2

Factorize the equation Compare the equation with au2  + bu + c  = 0We geta = 4 ,b=-8 c= 0To factorize the value  we can take 4u common there4u(u+2)= 0First zero4u        = 0u          = 0  second zerou+2      = 0u          = - 2  sum of zero       0 - 2        = - 2product of zero  0 * ( - 2 ) = 0
Sum  of zero , -b/a   = -(8/4)    = -2Product of zero,  c/a =  0/4      =  0hence we have verified that