Question

find the zeros of the following quadratic polynomial y square minus 4​

Answer 1

Answer:

let p (x) = y*2 - 4

=> y*2 - 4 = 0

=> y*2 = 0 + 4

=> y = 4 / 2

=> y = 2

Therefore, zero of the polynomial p (x) = 2

Answer 2

Answer:

-2 and 2

Step-by-step explanation:

y^2-4

y^(2) - 2^(2)

(y+2)(y - 2)

y = -2, y = 2