Find the zeros of the following quadratic polynomials 4s2 − 4s + 1.
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Answered by
1
Step-by-step explanation:
4s² - 4s +1 =0
4s² -2s-2s +1=0
2s( 2s -1) -1(2s-1) =0
(2s-1) (2s -1) =0
2s - 1 =0
2s= 1
s = 1/2
Answered by
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4s²-4s+1
4s²-2s-2s+1
2s(2s-1)-1(2s-1)
(2s-1) (2s-1)
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