Question

Find the zeros of the following quadratic polynomials and verofy the relationship between the zeros and the coefficients :- x2-15​

Answer 1

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Answer 2

AnsWer :

√15 and, -√15.

Solution :

We have equation.

$\tt \: {x}^{2} - 15 = 0.$

Compare with General Equation,

$\tt\dagger \: \: a {x}^{2} + bx + c = 0.$

Where as,

$\tt\: \red{a \neq0.}$

$\rule{90}1$

• a = 1.
• b = 0.
• c = -15.

We have Quadratic Formula.

$\tt \dagger \: \: x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

$\tt\mapsto x = \frac{ 0 \pm \sqrt{ {0}^{2} - 4 \times 1 \times - 15 } }{2}$

$\tt\mapsto x = \frac{ \pm\sqrt{60} }{2}$

$\tt\mapsto x = \frac{2 ( \pm\sqrt{15)} }{2}$

$\tt\mapsto x = \pm \sqrt{15} .$

Therefore, the value of x be √15 and -√15.