Question

find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients 2 x square - 9 x minus 45
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Answer 1

Answer:

I don't know the solution of this question

Answer 2

Step-by-step explanation:

2x^2 - 9x - 45

2x^2 + 6x - 15x - 45

2x ( x + 3 ) - 15 ( x + 3 )

( x + 3 ) ( 2x - 15 )

x = -3 , 15 / 2

alpha = -3 ; beta = 15 / 2

sum of zeroes = alpha + beta

= - 3 + 15 / 2

= -6 + 15 / 2

= 9 / 2

product of zeroes = alpha × beta

= -3 × 15 / 2 = -45 / 2

2x^2 - 9x - 45

a = 2 , b = -9 , c = -45

sum = - b / a

= - ( -9 ) / 2 = 9 / 2

product = c / a

= -45 / 2

hence , verified.

hope it helps..........

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