Question

find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients of x^2+3x-10​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

➤Let f(x) = x² + 3x ˗ 10

➤x² + 5x ˗ 2x ˗ 10

➤x(x + 5) ˗ 2(x + 5)

➤(x ˗ 2) (x + 5)

To find the zeroes, set f(x) = 0, then

either x ˗ 2 = 0 or x + 5 = 0

➤ x = 2 or x = −5.

So, the zeroes of f(x) are 2 and −5.

Again,

${\bold{\sf{Sum \: \: of \: \: zeroes \: \: = \: \: 2 \: + \: (-5) = \: \: -3 \: \: = \: \frac{(-3)}{1}}}}$

${\bold{\sf{➤ \: \: \: \: \: \frac{(-b)}{a}}}}$

${\bold{\sf{\frac{(-Coefficient \: \: of \: \: x)}{(Cofficient \: \: of \: \: x²)}}}}$

${\bold{\sf{Product \: \: of \: \: zeroes \: \: = \: \: (2)(-5) \: \: = \: \: -10 \: \: = \: \: \frac{(-10)}{1}}}}$

${\bold{\sf{➤ \: \: \: \: \: \frac{c}{a}}}}$

${\bold{\sf{\frac{Constant \: \: term}{Coefficient \: \: of \: \: x²}}}}$