find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients 6 x square - 3 - 7x
Attachments:
Answers
Answered by
9
hey there is answer !!
I hope you help !!
=6x²-7x-3
=6x²+2x-9x-3
=2x(3x+1)-3(3x+1)
=(2x-3)(3x+1)
⇒2x-3=0 or ⇒3x+1=0
⇒x=3/2 or ⇒ x= - 1/3
α=3/2 ,β= - 1/3
⇒α+β= -b/a
⇒3/2+(-1/3)= - (-3)/6
⇒3/2-1/3=1/2
⇒7/6 =1/2
⇒αβ=c/a
⇒ 3/2(-1/3)= -7/6
⇒-1/2= -7/6
⇒1/2=7/6
Given,
6x²-7x - 3
to find the zeroes of the polynomial,
6x²-7x - 3 = 0
6x²-9x +2x -3 = 0
3x(2x-3) + 1(2x -3) = 0
(3x+1) (2x-3) = 0
x = -1/3 or 3/2
sum of the zeroes = 3/2 - 1/3 = 7/6 = - ( co-efficient of x) / co-efficient of x²
product of the zeroes = -1/3 × 3/2 = -1/2 = constant / co-efficient of x²
regards you ....
I hope you help !!
=6x²-7x-3
=6x²+2x-9x-3
=2x(3x+1)-3(3x+1)
=(2x-3)(3x+1)
⇒2x-3=0 or ⇒3x+1=0
⇒x=3/2 or ⇒ x= - 1/3
α=3/2 ,β= - 1/3
⇒α+β= -b/a
⇒3/2+(-1/3)= - (-3)/6
⇒3/2-1/3=1/2
⇒7/6 =1/2
⇒αβ=c/a
⇒ 3/2(-1/3)= -7/6
⇒-1/2= -7/6
⇒1/2=7/6
Given,
6x²-7x - 3
to find the zeroes of the polynomial,
6x²-7x - 3 = 0
6x²-9x +2x -3 = 0
3x(2x-3) + 1(2x -3) = 0
(3x+1) (2x-3) = 0
x = -1/3 or 3/2
sum of the zeroes = 3/2 - 1/3 = 7/6 = - ( co-efficient of x) / co-efficient of x²
product of the zeroes = -1/3 × 3/2 = -1/2 = constant / co-efficient of x²
regards you ....
smartAbhishek11:
hii
Answered by
6
HEY MATE THE ANSWER OF BOTH THE QUESTIONS ARE IN THE ATTACHMENT
PLEASE MARK THE ANSWER AS BRAINLIEST
Attachments:
Similar questions
Biology,
6 months ago
Economy,
6 months ago
English,
6 months ago
Hindi,
11 months ago
Accountancy,
1 year ago
Economy,
1 year ago
Social Sciences,
1 year ago