Question

find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients​

Answer 1

Here is your Ans

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$= > 5 {x}^{2} - 29x + 20 = 0 \\ = > 5 {x}^{2} - 25x - 4x + 20 = 0 \\ = > 5x(x - 5) - 4(x - 5) \\ = > x = \frac{4}{5} \: \: or \: \: x = 5 \\ \\ \\ verification \\ \\ \\ \alpha + \beta = \frac{ - b}{a} \\ = > \frac{4}{5} + 5 = \frac{ - ( - 29)}{5} \\ = > \frac{29}{5} = \frac{29}{5} \\ \\ \alpha \times \beta = \frac{c}{a} \\ = > \frac{4}{5} \times 4 = \frac{20}{5} \\ = > \frac{20}{5} = \frac{20}{5} \\ \\ verified$

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Answer 2

Answer:-

$(5x - 29x + 20 = 0) \\ (5x2 - 25 \times - 4x + 20 = 0) \\( 5x(x - 5) - 4(x - 5)) \\ ( \times = 5/4) \\ (\times = 5)$

Now time to verification

α×β= a/−b

$(5/4+5=5( - 29)) \\ (5/29 = 5/29a \times b = ac) \\ (5/4 \times 4 = 5/20) \\ (5/20 = 5/20)$

20/5 =20/5

Hence Verified the answer