Question

Find the zeros of the following quadratic ᴩᴏʟyɴᴏᴍɪᴀʟꜱ 15x2 + 16x + 4​

Answer 1

Answer:

15x2+16x+4=gonna have to do the factorisation method and will get it

Answer 2

$\large\underline{\sf{Solution-}}$

Given polynomial is

$\rm :\longmapsto\:f(x) = {15x}^{2}+16x + 4$

Using concept of middle terms,

$\rm :\longmapsto\:f(x) = {15x}^{2}+10x + 6x + 4$

$\rm :\longmapsto\:f(x) = 5x(3x + 2) + 2(3x + 2)$

$\rm :\longmapsto\:f(x) = (5x + 2)(3x + 2)$

To find, zeroes of f(x), put f(x) = 0

$\rm :\longmapsto\:(5x + 2)(3x + 2) = 0$

$\rm :\longmapsto\:x = - \dfrac{2}{5} \: \: or \: \: - \dfrac{2}{3}$

More to know

Let us assume a quadratic polynomial ax² + bx + c then

$\boxed{{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}$

and

$\boxed{{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}$