Question

find the zeros of the following quaratic polynomial and verify the relationship between the zeros and the coefficient: 6x²-3-7x​

Answer 1

Given

We have given a quadratic equation 6x²-7x-3

To Find

We have to find zeros of given Equation and hence verify it's relationship between the zeroes.

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Firstly we have to find the zeroes

➞6x²-7x-3

➞6x²-9x+2x-3

➞3x(2x-3)+1(2x-3)

➞(3x+1)(2x-3)=0

➞3x+1=0

x= -1/3

➞2x-3=0

x= 3/2

Now, verifying the relationship

6x²-7x-3

a= 6 ,b = -7 & c= -3

Let λ = -1/3 & β = 3/2

Sum of its zeroes = -b/a

λ+β= -b/a

➞ -1/3 +3/2 = -(-7/6)

➞-2+9/6= 7/6

➞7/6 = 7/6

Product of its zeroes = c/a

λβ= c/a

➞ -1/3×3/2= -3/6

➞-3/6 = -3/6

➞-1/2 = -1/2

Hence,the relationship between the zeroes and the coefficient is verified.

Answer 2

Step-by-step explanation:

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