Question

find the zeros of the following.
${4u}^{2} + 8u$

Answer 1

Heya User ✌

Here's your answer friend,

_________________________________

==> 4u² + 8u = 0

==> 4u(u + 2) = 0

==> 4u = 0 and (u + 2) = 0

==> u = 0 and u = -2

➡are the required zeroes of the given polynomial.

HOPE IT HELPS YOU :)

_________________________________

#BEBRAINLY
#TOGETHER WE GO FAR
#☺☺☺

Answer 2

Heya Dear User ☺️
_______________

For finding its zeroes,

{4u}^2+ 8u = 0

4u ( u + 2 ) = 0

so,

4u = 0 and u +2 = 0

u = 0 and u = -2 are zeroes

_____________

hope this helps !