Math, asked by lorena1hh2004, 6 months ago

find the zeros of the function
f(x)=9x²-3x-2

Answers

Answered by Anonymous
2

ɢɪᴠᴇɴ :-

9x²-3x - 2 = 0

9x²-6x + 3x - 2 = 0

3x (3x -2 ) + 1( 3x - 2) = 0

( 3x - 2)( 3x + 1) = 0

ᴛʜᴇʀᴇꜰᴏʀᴇ,

3x - 2 = 0

3x = 2

x = 2/3

ꜱɪᴍɪʟᴀʀʟy,

3x + 1 = 0

3x = -1

x = -1/3

ꜱᴏ, ᴛʜᴇ ᴢᴇʀᴏᴇꜱ ᴏꜰ ᴩᴏʟyɴᴏᴍɪᴀʟ 9x²-3x-2 are:-

x = 2/3

x = -1/3

ʜ ʜɪ ʜʟ y✌️

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