find the zeros of the function
f(x)=9x²-3x-2
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ɢɪᴠᴇɴ :-
9x²-3x - 2 = 0
9x²-6x + 3x - 2 = 0
3x (3x -2 ) + 1( 3x - 2) = 0
( 3x - 2)( 3x + 1) = 0
ᴛʜᴇʀᴇꜰᴏʀᴇ,
3x - 2 = 0
3x = 2
x = 2/3
ꜱɪᴍɪʟᴀʀʟy,
3x + 1 = 0
3x = -1
x = -1/3
ꜱᴏ, ᴛʜᴇ ᴢᴇʀᴏᴇꜱ ᴏꜰ ᴩᴏʟyɴᴏᴍɪᴀʟ 9x²-3x-2 are:-
x = 2/3
x = -1/3
ʜᴏᴩᴇ ᴛʜɪꜱ ʜᴇʟᴩᴇᴅ yᴏᴜ✌️
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